31 March 2008

FAQ: What is the scoring function to be used?

What is the scoring function to be used?

d = estimated_RUL-actual_RUL;

score(d<0) = exp(-d(d<0)/13)-1;
score(d>0) = exp(d(d>0)/10)-1;

score = sum(score)

2 comments:

Leo said...
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Anonymous said...

What does it mean (d<0) and (d>0) in the right side of the equations? A 1 if it is true?

It isn't the same that

score(d<0) = exp(-d/13)-1;
score(d>0) = exp(d/10)-1


Thanks